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Error message: Cannot convert undefined or null value to object (throttled)


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I am trying to create a post request that returns an array of gross pay items. I thought I did it correctly and it said that my request was successful, but seconds later I got this big red alert that said “Cannot convert undefined or null value to object (throttled).”

I have attached the return code I am using and the model of the data it should be returning. I also attached a photo of the error message. Does anyone have any idea what is going on here?

Here is the Model of the data that should be returned. I am trying to pull in only the grossPayItems Array.
Here is the code I am using to pull in the grossPayItems. I have tried wrapping it in an array and not wrapping it in an array with the same results both times.
Here is the error message it is giving.

 

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Best answer by Danvers 26 March 2020, 13:23

Hi @jacob_nolley - were you able to get to the bottom of this one? If not please let me know and I can ask the Support Team to take a look for you. 

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Userlevel 7
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@jacob_nolley - Try to `z.console.log(results)`. Is it an object or a null/empty response? You probably need to check if the response is an object before returning it. Otherwise just return an empty array if it’s a search action, or an empty object if it’s a create action.

Userlevel 7
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@jacob_nolley - Here’s what I meant:

const results = z.JSON.parse(response.content);

z.console.log(results); // <--- Here

return results;

To answer your question, you should actually check if the result is an array, like this:

const results = z.JSON.parse(response.content);
if (Array.isArray(results)) {
return results;
} else {
return [];
}

 

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@ikbelkirasan

I did what you said and it said that that my results were not an array.

 

When my code looked like this, it said that my results were not an array:

const results = z.JSON.parse(response.content);

z.console.log(results.grossPayItems);

return results.grossPayItems;  

});

 

When my code looked like this, it gave me the red error code:

const results = z.JSON.parse(response.content);

z.console.log([results.grossPayItems]);

return [results.grossPayItems];  

});

 

When my code looked like this, it gave me the results pictured below. I am trying to get all of the results from the subObject “grossPayItems”:

const results = z.JSON.parse(response.content);

z.console.log(results);

return results;  

});

 

Userlevel 7
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Hi @jacob_nolley - were you able to get to the bottom of this one? If not please let me know and I can ask the Support Team to take a look for you. 

Userlevel 7
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Thanks for letting us know, I’m glad that you were able to find a workaround 🙌

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Do you mean like this? I tried this and I got the same result. It is a Search action. Is there a way to specify that an empty array is okay?

 

Userlevel 7
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@jacob_nolley  - I suspect the API is returning an object, not an array. So, try the snippet below:

const results = z.JSON.parse(response.content);

const grossPayItems = results.grossPayItems;
if (Array.isArray(grossPayItems)) {
return grossPayItems;
} else {
return [];
}
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@ikbelkirasan 

I received [ ] as a response. Do you know how I could fix this?

 

 

Userlevel 7
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@jacob_nolley  - Can you post any console logs you got when you used `z.console.log` as I mentioned earlier? It’s important to see what the API response looks like exactly.

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@ikbelkirasan 

When I do the z.console.log, it says “no logs to show”

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Heyy @Danvers,

 

I fortunately I didnt. Instead, I just implemented a work around and have been able to get that to work!

 

Thank you,

Jacob