@HugoT 

This might be helpful for your scenario: 

@robschmidt Sorry that didn’t do the job.

Is there another way?

We need to go from

1. A (url)
2. B (url)
3. C (url)
4. D (url)

To > Function or Zap that randomizes >

1. C (url)
2. B (url)
3. D (url)
4. A (url)

Hi there @HugoT -

In order for me to best assist you, can you please provide some additional information regarding the set up of your Zap (trigger and action(s) used)? A screenshot of those would be excellent in order to get a closer look and see what is and is not possible, or if there are any workarounds to be found!

Please omit any personal information from the screenshots. 

@chanelle thank you for your reply

Please see below the flow:
Additional information: at step 4 I select the images i want to use for the 4 different formats; It is the generated stories (step 6, 7, 8 and 9 > they provide a link as output) that i want to shuffle for the steps 11, 13, 15 and 17.

Apologies @HugoT as I should have clarified, can you please provide screenshots in a similar fashion to this. That way I can see the nitty-gritty details that lay within the steps you indicated above. 

Again, apologies for the inconvenience and hoping to hear back soon! 

@chanelle 

I believe these screenshots are the most valuable

Same for step 7, 8 and 9 (but different input fields leading to different generated outputs/urls


Step 11: (sending an email with the output/url from step 6) So step 13 has as attachment the output of step 7, etc… I want the outputs used to shuffle/randomize
 

Does this clarify?
 

Hi @HugoT 

Good question.

If you are looking to randomize an array’s items, then try using a Code step.

You can ask ChatGPT for the code to do the randomization. (may need to be tweaked to work in the Zap Code step)

Example: https://chat.openai.com/share/b8b1e8b2-bc63-420e-b9a8-e9802d3e6f59

let Set = inputData.Set;
if (Set) {
  Set = Set.split(",");
}

let randomizeArray = (array) => {
  for (let i = array.length - 1; i > 0; i--) {
    const j = Math.floor(Math.random() * (i + 1));
    >arrayai], arrayaj]] = ]arrayaj], arrayai]];
  }
  return array;
};

let SetX = randomizeArray(r...Set]);

output = u{Set, SetX}];

@HugoT 

Related Zapier Topic:

Great thank you!

Works well.

Awesome! So glad to hear Troy was able to get you and up running with his recommendations.

Let us know if you have any other questions - we're always happy to help.