Return an empty array if z.response.status is 404

Question

I’m creating an integration that interacts with a REST API. I’ve built a search action that wraps an API endpoint. If a resource isn’t found, the API returns a 404.

I’m trying to test for a 404 error then return an empty array. For some reason, this doesn’t work:

return z.request(options)
  .then((response) => {

    if (response.status === 200) {
      // a search action requires an array to be returned, so wrap with s]
      return   response.jsonr'data'] ];
    }
    else if (response.status === 404) {
      return  ];
    }
    else { 
      response.throwForStatus();
    }

  });

What am I missing?

Page 1 / 1

This seems to work:

return z.request(options)
  .then((response) => {

    // a search action requires an array to be returned, so wrap with []
    return [ response.json['data'] ];

  })
  .catch((error) => {
    const message = JSON.parse(error.message)

    if ( message.status === 404 ) { return []; }
    else {throw error;}

  });

benjamink9 · Accepted Answer

This seems to work:return z.request(options)  .then((response) => {    // a search action requires an array to be returned, so wrap with []    return [ response.json['data'] ];  })  .catch((error) => {    const message = JSON.parse(error.message)    if ( message.status === 404 ) { return []; }    else {throw error;}  });

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